On the solvability of the initial boundary value problem for schrodinger systems in conical domains

1. Introduction The initial boundary value problems for Schr¨odinger equations in the cylinders with base containing conical points were established in [2,3]. Such problems for parabolic systems have been studied in Sobolev spaces with weights [4,5]. We are concerned with initial boundary value problems for Schr¨odinger systems in cylinders with base containing conical point. The paper is organized is the following way. In Section 2 we define the problem. In Section 3 we establish the unique existence of the generalized solution of the problem. Finally, in Section 4 we apply the obtained results to a problem of mathematical physics.

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JOURNAL OF SCIENCE OF HNUE Natural Sci., 2010, Vol. 55, No. 6, pp. 82-89 ON THE SOLVABILITY OF THE INITIAL BOUNDARY VALUE PROBLEM FOR SCHRO¨DINGER SYSTEMS IN CONICAL DOMAINS Nguyen Thi Lien Hanoi National University of Education E-mail: Lienhnue@gmail.com Abstract. In this paper, we consider the initial boundary value problem for Schro¨dinger systems in the cylinders with base containing the conical point. The existence and the uniqueness of the generanized solution of this problem are given. Keywords: Initial boundary value problem, generalized solution, cylinders with conical base. 1. Introduction The initial boundary value problems for Schro¨dinger equations in the cylinders with base containing conical points were established in [2,3]. Such problems for parabolic systems have been studied in Sobolev spaces with weights [4,5]. We are concerned with initial boundary value problems for Schro¨dinger sys- tems in cylinders with base containing conical point. The paper is organized is the following way. In Section 2 we define the prob- lem. In Section 3 we establish the unique existence of the generalized solution of the problem. Finally, in Section 4 we apply the obtained results to a problem of mathematical physics. 2. Notations and formulation of the problem Let Ω be a bounded domain in Rn (n ≥ 2) with the boundary ∂Ω. We suppose that S = ∂Ω \ {0} is a smooth manifold and Ω is in a neighbourhood U of the origin 0 coincides with the cone K = {x : x/ | x |∈ G}, where G is a smooth domain on the unit sphere Sn−1 in Rn. Let T be a positive real number or T =∞. Set Ωt = Ω× (0, t), St = S × (0, t). For each multi-index α = (α1, . . . , αn) ∈ Nn, |α| = α1 + · · ·+ αn, the symbol Dα = ∂|α|/∂xα11 ...∂x αn n denotes the generalized derivative of order α with respect to x = (x1, ..., xn); ∂ k/∂tk is the generalized derivative of order k with respect to t. Let u = (u1, ..., us) be a complex-valued vector function defined on ΩT . We use notation: Dαu = (Dαu1, ..., D αus); utj = ∂ ku/∂tk = (∂ju1/∂t j , .., ∂jus/∂t j). Let us introduce some functional spaces used in this paper (see [1]): 82 On the solvability of the initial boundary value problem for Schro¨dinger systems... We use H l(Ω) be the space of functions defined in Ω with the norm ‖u‖Hl(Ω) = ( l∑ |α|=0 ∫ Ω |Dαu|2dx) 12 Let X, Y be Banach spaces. Denote by L2((0, T );X) the space consisting of all measureable functions u : (0, T ) −→ X with the norm ‖u‖L2((0,T );X) = ( ∫ T 0 ‖u(t)‖2Xdt ) 1 2 and by H((0, T );X, Y ) the space consisting of all functions u ∈ L2((0, T );X) such that the generalized derivative ut exists and belongs to L2((0, T );Y ). The norm in H((0, T );X, Y ) is defined by ‖u‖H((0,T );X,Y ) = (‖u‖2L2((0,T );X) + ‖ut‖2L2((0,T );Y )) 12 Now we introduce a differential operator of order 2m L(x, t,D) = m∑ |p|,|q|=0 (−1)|p|Dp(apq(x, t)Dq), where apq are s×s matrices smooth elements of which are in ΩT , apq = (−1)|p|+|q|a?pq (a∗qp is the transportated conjugate matrix to apq).We assume there exists a constant c0 > 0 independing on t such that: ∀ξ ∈ Rn \ {0}, ∀η ∈ Cs \ {0} :∑ |p|=|q|=m apq(x, t)ξ pξqηη ≥ c0|ξ|2m|η|2, (2.1) where ξp = ξp11 ...ξ pn n , ξ q = ξq11 ...ξ qn n . We introduce also a system of boundary operators Bj = Bj(x, t,D) = ∑ |p|≤µj bj,p(x, t)D p, j = 1, ..., m, on S. Suppose that bj,p(x, t) are s× s matrices smooth elements of which are in ΩT and ordBj = µj ≤ m− 1 for j = 1, ..., χ, m ≤ ordBj = µj ≤ 2m− 1 for j = χ+ 1, ..., m. Assume that coefficients ofBj are independent of t if ordBj < m and {Bj(x, t,D)}mj=1 is a normal system on S for all t ∈ [0, T ], i.e., the two following conditions are satisfied: 83 Nguyen Thi Lien (i) µj 6= µk for j 6= k, (ii) Boj (x, t, ν(x)) 6= 0 for all (x, t) ∈ ST , j = 1, ..., m. Here ν(x) is the unit outer normal to S at point x and Boj (x, t,D) is the principal part of Bj(x, t,D), Boj = B o j (x, t,D) = ∑ |p|=µj bj,p(x, t)D p, j = 1, ..., m. Furthermore, Boj (0, t, ν(x)) 6= 0 for all x ∈ S closed enough to the origin 0. We set HmB (Ω) = { u ∈ Hm(Ω) : Bju = 0 on S for j = 1, .., χ } with the same norm in Hm(Ω) and B(t, u, v) = m∑ |p|,|q|=0 ∫ Ω apqD quDpvdx, t ∈ [0, T ]. Doing the same in the Garding’s inequality, we have: Lemma 2.1. Suppose that coefficients of the operator L(x,t,D) satisfy condition (2.1). Then there exists two constant µ0 and λ0 such that (−1)mB(t, u, u) ≥ µ0‖u(x, t)‖2Hm(Ω) − λ0‖u(x, t)‖2L2(Ω) for all functions u(x, t) ∈ H((0, T );HmB (Ω), H−mB (Ω)). Thus, set u = eiλ0tv if necessary, we can suppose that (−1)mB(t, u, u) ≥ µ0‖u(x, t)‖2Hm(Ω) (2.2) for all u ∈ HmB (Ω) and t ∈ [0, T ]. Applying Green’s formula, we can assume that it can be choose boundary operators Φj on ST , j = 1, ..., m such that B(t, u, v) = ∫ Ω Luv + χ∑ j=1 ∫ S ΦjBjvds+ m∑ j=χ+1 ∫ S BjΦjvds. (∗) Denote H−mB (Ω) the dual space to H m B (Ω). We write 〈 ., . 〉 to stand for the pair- ing between HmB (Ω) and H −m B (Ω), and (., .) to define the inner product in L2(Ω). We then have the continuous imbeddings HmB (Ω) ↪→ L2(Ω) ↪→ H−mB (Ω) with the equation 〈 f, v 〉 = (f, v) for f ∈ L2(Ω) ⊂ H−mB (Ω), v ∈ HmB (Ω). 84 On the solvability of the initial boundary value problem for Schro¨dinger systems... We study the following problem in the cylinder ΩT : (−1)m−1iL(x, t,D)u− ut = f(x, t) in ΩT , (2.3) Bju = 0, on ST , j = 1, ..., m, (2.4) u |t=0= φ, on Ω, (2.5) where f ∈ L2((0, T );HmB (Ω)) and φ ∈ L2(Ω) are given functions. The solution u(x, t) is searched in the generalized sense. That means u ∈ H((0, T );HmB (Ω), H−mB (Ω)) is called a generalized solution of the problem (2.3)- (2.5) if u(., 0) = φ and the equality (−1)m−1iB(t, u, v)− 〈ut, v〉 = 〈f(t), v〉 (2.6) holds for a.e. t ∈ (0, T ) and all v ∈ HmB (Ω). 3. The unique solvability of the problem Theorem 3.1. Suppose that coefficients of the operator L(x,t,D) satisfy condition (2.2). Then problem (2.3)-(2.5) has at most one generalized solution in the space generalized solution u ∈ H((0, T );HmB (Ω), H−mB (Ω)). Proof. Suppose u1(x, t), u2(x, t) are two generalized solutions of problem (2.3)-(2.5) inH((0, T );HmB (Ω), H −m B (Ω)). Denote u(x, t) = u 1(x, t)−u2(x, t). Arccording to the denifition of generalized solutions, substituting v := u into (2.6), then integrating both sides of the obtained equality with respect to t from 0 to b (b > 0), we arrive at (−1)m−1i ∫ b 0 B(t, u(., t), u(., t))dt− ∫ b 0 〈 ut, u(., t) 〉 dt = 0. Thus (−1)m ∫ b 0 B(t, u(., t), u(., t))dt− i ∫ b 0 〈 ut, u(., t) 〉 dt = 0. (3.1) Since ∫ b 0 〈 ut, u(., t) 〉 dt = ‖u(b)‖2L2(Ω) − ∫ b 0 〈 u, ut(., t) 〉 dt, we get ∫ b 0 〈 ut, u(., t) 〉 dt = 1 2 ‖u(b)‖2L2(Ω). Adding (3.1) with its complex conjugate, we discover∫ b 0 B(t, u(., t), u(., t))dt = 0 Using the inequality (2.2), we have∫ b 0 ‖u‖2Hm B (Ω)dt ≤ ∫ b 0 B(t, u(., t), u(., t))dt = 0, 85 Nguyen Thi Lien so ‖u‖2L2((0,b);HmB (Ω)) = ∫ b 0 ‖u‖2L2((0,T );HmB (Ω))dt = 0. This implies u ≡ 0 on [0, b]. Therefore, u ≡ 0 on ΩT . The proof of the uniquence of generalized solution is completed. Theorem 3.2. Suppose that f ∈ L2((0, T );H−mB (Ω)), φ ∈ L2(Ω) and the conditions of Theorem 3.1 is fulfilled. Then there exists a generalized solution in generalized solution u ∈ H((0, T );HmB (Ω), H−mB (Ω)) of the problem (2.3)-(2.5) which satisfies ‖u‖2 H((0,T );Hm B (Ω),H−m B (Ω)) ≤ C(‖φ‖2L2(Ω) + ‖f‖2L2((0,T );H−mB (Ω))), where C is a constant independent of φ, f and u. Proof. Suppose {ψk(x)}∞k=1 be a system functions in HmB (Ω), which is orthonormal in L2(Ω) and its linear closure is just H m B (Ω). We look for u N(x, t) in the form: uN(x, t) = N∑ k=1 CNk (t)ψk(x), where {CNk (t)}Nk=1 is the solution of the ordinary differ- ential system: (−1)m−1i m∑ |p|,|q|=0 ∫ Ω apqD quNDpψldx− ∫ Ω uNt ψldx = 〈 f, ψl 〉 , l = 1, ..., N (3.2) CNk (0) = Ck = (φ, ψk), k = 1, ..., N. (3.3) After multiplying both sides of (3.2) by CNl (t), taking sum with respect to l from 1 to N and integrating with respect to t from 0 to τ (τ > 0), we get (−1)m−1i τ∫ 0 B(t, uN , uN)dt− τ∫ 0 (uNt , u N)dt = τ∫ 0 〈 f, uN 〉 dt. From this equality we obtain (−1)m τ∫ 0 B(t, uN , uN)dt− 1 2 i (‖u(τ)‖2L2(Ω) − ‖u(0)‖2L2(Ω)) = i τ∫ 0 〈 f, uN 〉 dt. (3.4) Adding (3.4) with its complex conjugate, we have (−1)m−1 τ∫ 0 B(t, uN , uN)dt = Im τ∫ 0 〈 f, uN 〉 dt 1 2 (‖u(τ)‖2L2(Ω) − ‖u(0)‖2L2(Ω)) = −Re τ∫ 0 〈 f, uN 〉 dt. 86 On the solvability of the initial boundary value problem for Schro¨dinger systems... Noting that |(−1)m−1 τ∫ 0 B(t, uN , uN)dt| ≥ µ‖uN‖2L2((0,τ);HmB (Ω)) ‖uN(0)‖2L2(Ω) = ‖ N∑ k=1 (φ, ψk)ψk‖2L2(Ω) ≤ ‖φ‖2L2(Ω) and |Im τ∫ 0 〈 f, uN 〉 dt| − |Re τ∫ 0 〈 f, uN 〉 dt| ≤ 2 τ∫ 0 ‖f‖H−m B (Ω)‖uN‖HmB (Ω) ≤ ‖uN‖2L2((0,τ);HmB (Ω)) + 1  ‖f‖2 L2((0,τ);H −m B (Ω)) , So we have ‖uN‖2L2((0,τ);HmB (Ω)) ≤ C (‖f‖2 L2((0,τ);H −m B (Ω)) + ‖φ‖2L2(Ω) ) . Letting τ tend to T , we get ‖uN‖2L2((0,T );HmB (Ω)) ≤ C (‖f‖2 L2((0,T );H −m B (Ω)) + ‖φ‖2L2(Ω) ) . (3.5) Now, fix any v ∈ HmB (Ω) with ‖v‖HmB (Ω) ≤ 1 and write v = v1 + v2, where v1 ∈ span{ψl}Nl=1, (v2, ψl)L2(Ω) = 0, l = 1, ..., N. Since ‖v‖HmB (Ω) ≤ 1, ‖v1‖HmB (Ω) ≤ 1. We obtain from (3.2) that −(uNt , v1) + (−1)m−1iB(t, uN , v1) = 〈 f, v1 〉 . Thus, 〈 uNt , v 〉 = (uNt , v) = (u N t , v1) = (−1)m−1iB(t, uN , v1)− 〈 f, v1 〉 . Since ‖v1‖Hm B (Ω) ≤ 1, ‖uNt ‖H−m B (Ω) ≤ | 〈 uNt , v 〉| ≤ |B(t, uN , v1)|+ |〈f, v1〉| ≤ C(‖f‖H−m B (Ω) + ‖uN‖HmB (Ω) ) . Therefore, by (3.5), ‖uNt ‖2L2((0,T );H−mB (Ω)) ≤ C (‖f‖2 L2((0,T );H −m B (Ω)) + ‖uN‖2L2((0,T );HmB (Ω)) ) ≤ C(‖f‖2 L2((0,T );H −m B (Ω)) + ‖φ‖2L2(Ω) ) . From this inequality and (3.5) we get ‖uNt ‖2H((0,T );Hm B (Ω),H−m B (Ω)) ≤ C(‖f‖2 L2((0,T );H −m B (Ω)) + ‖φ‖2L2(Ω) ) , (3.6) 87 Nguyen Thi Lien where C is the constant independent of φ, f and N . Because {uN} is bounded in Hilbert space H((0, T );HmB (Ω), H−mB (Ω)), we can choose a subsequence weakly convergent to u(x, t) ∈ H((0, T );HmB (Ω), H−mB (Ω)). We will prove that u(x, t) is a generalized solution of problem (2.3)-(2.5). Fix a positive real number τ, τ ≤ T and a positive integer h. Take a function η ∈ L2((0, τ);H m B (Ω)) in the form η(x, t) = h∑ l=1 dl(t)ψl(x), (3.7) where dl(t) are smooth functions defined on [0, τ ]. Multiplying both sides of (3.2) with N ≥ h by dl(t), taking sum with respect to l from 1 to h and integrating with respect to t from 0 to τ , we have (−1)m−1i τ∫ 0 B(t, uN , η)dt− τ∫ 0 〈 uNt , η) 〉 dt = τ∫ 0 〈 f, η 〉 dt. Letting N tend to ∞, we have (−1)m−1i τ∫ 0 B(t, u, η)dt− τ∫ 0 (ut, η)dt = τ∫ 0 〈 f, η 〉 dt. (3.8) Since the set of functions of the form (3.7) is dense in L2((0, τ);H m B (Ω)), the equality (3.8) holds for all η ∈ L2((0, τ);HmB (Ω)). This implies (−1)m−1iB(t, u, v)− 〈ut, v〉 = 〈f(t), v〉 holds for a.e. t ∈ (0,+∞) and all v ∈ HmB (Ω).The inequality in the theorem is followed from (3.6). Now, we will prove that u(., 0) = φ. An intergration by parts from (3.8) yields (−1)m−1i τ∫ 0 B(t, u, η)dt− τ∫ 0 (u, ηt)dt+ (u(., 0), η(., 0)) = τ∫ 0 〈 f, η 〉 dt (3.9) holds for all η ∈ C1([0, τ ], HmB (Ω)) satisfying η(., τ) = 0. We have (−1)m−1i τ∫ 0 B(t, uN , η)dt− τ∫ 0 (uN , ηt)dt+ (u N(., 0), η(., 0)) = τ∫ 0 〈 f, η 〉 dt. Passing to the limit as N →∞ with noting that uN(., 0)→ φ in L2(Ω), we get (−1)m−1i τ∫ 0 B(t, u, η)dt− τ∫ 0 (u, ηt)dt+ (φ, η(., 0)) = τ∫ 0 〈 f, η 〉 dt. (3.10) 88 On the solvability of the initial boundary value problem for Schro¨dinger systems... Comparing (3.9) and (3.10),we obtain (u(., 0), η(., 0)) = (φ, η(., 0)). Since η(., 0) ∈ HmB (Ω) is arbitrary u(., 0) = φ.Theorem 3.1 is proved. 4. An example In this section we apply the previous results to the Cauchy-Dirichlet problem for the wave equation. We consider the following problem: 4u− utt = f(x, t), (x, t) ∈ ΩT , (4.1) u|t=0 = ut|t=0 = 0, x ∈ Ω, (4.2) u|ST = 0, (4.3) where 4 is the Laplace operator. By o H1(Ω) we denote the completion of o C∞(Ω) in the norm of the spaceH1(Ω). ThenH((0, T );H1B(Ω), H −1 B (Ω) = H((0, T ); o H1(Ω), o H−1(Ω)). From this fact and Theorem 3.1 and 3.2 we obtain following results. Theorem 4.1. Suppose that f ∈ L2((0, T ); o H−1(Ω)), φ ∈ L2(Ω). 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